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    (浙江宁波11月份月考)2020-2021学年第一学期七年级数学练习题

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    (浙江宁波11月份月考)2020-2021学年第一学期七年级数学练习题

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    这是一份(浙江宁波11月份月考)2020-2021学年第一学期七年级数学练习题,文件包含浙江宁波2020-2021学年第一学期七年级数学浙教版docx、浙江宁波2020-2021学年第一学期七年级数学浙教版参考答案及评分建议docx等2份试卷配套教学资源,其中试卷共7页, 欢迎下载使用。
    一、选择题(每小题 3 分,共 30 分)
    二、填空题(每小题 4 分,共 24 分)
    11.±312.12
    13.-414.  5
    2
    15.-4 039x2 02016.20
    三、解答题(本大题有 8 小题,共 66 分)
    17.(本题 6 分)
    解:(1)原式 8  (18)  4
    9
    =-8-8
    =-16.···················································································3 分
    1
    2
    3
    4
    5
    6
    7
    8
    9
    10
    B
    C
    A
    B
    D
    C
    B
    A
    D
    D
    (2)原式
    =
    5  3  (
    5
     3 
     2)
    5
    5  2
    =-1. ····················································································3 分
    18.(本题 6 分)
    解:(1)移项,得 4x-2x=5+1,
    19.(本题 6 分)
    解:如图所示(答案不唯一):
    ···················································4 分
    ·····················································6 分
    20.(本题 8 分)
    解:2A+B=2(-a2+2ab+2b2)+2a2-2ab-4b2
    =-2a2+4ab+4b2+2a2-2ab-4b2
    合并同类项,得 2x=6,
    系数化为 1,得 x=3. ································
    ································
    ·······
    3 分
    (2)去分母,得 2(2x-5)+3(3-x)=12,
    去括号,得 4x-10+9-3x=12,
    移项、合并同类项,得 x=13.································
    ····························
    3 分
    =2ab, ·························································································5 分
    当 a  2 , b  3 时,原式=2ab= 2  ( 2)  3  2 .8 分
    3232
    21.(本题 8 分)
    解:(1)由题意,得 m+1=3 且 3-n=0,
    ∵x=1,
    ∴x3+2x2+2 020
    =1+2+2 020
    =2 023.····················································································8 分
    22.(本题 10 分)
    解:(1)由题意,得 3a-4=2(1-2a)-3, ························································3 分
    3a-4=2-4a-3,
    3a+4a=2-3+4,
    7a=3,
    解得a  3 .···················································································5 分
    7
    (2)当 1-2a 与 3a-4 互为相反数时,
    1-2a+3a-4=0,解得 a=3, ······························································7 分
    23.(本题 10 分)
    解:(1)设小明 3 月份的存取金额为 x 元.
    由题意,得 500+x+(-150)+600+(-250)=400,4 分
    解得 x=-300, ···············································································6 分答:小明 3 月份取出 300 元.
    (2)2 月累计:500 元;
    3 月累计:500+(-300)=200(元),
    4 月累计:200+(-150)=50(元),
    5 月累计:50+600=650(元),
    6 月累计:400 元,
    所以小明储蓄卡上 5 月份的金额最多. ··············································10 分
    24.(本题 12 分)
    ∴m=2,n=3, ································································
    ···············
    2 分
    ∴mn+(m-n)2 021=23+(2-3)2 021=8-1=7. ································
    ············
    4 分
    (2)由(1)得,xm+1+2x2+3x-nx+2 020=x3+2x2+2 020. ·······························
    6 分
    此时 1-2a=1-2×3 =-5,3a-4=3×3 -4=5,
    所以这个数是 52=25;
    当 1-2a 与 3a-4 相等时,
    1-2a=3a-4,解得 a=1, ································
    ································
    9 分
    此时 1-2a=1-2×1 =-1,3a-4=3×1 -4=-1,
    所以这个数是(-1)2=1,
    综上,这个数是 25 或 1.································
    ································
    10 分
    解:(1)17×3.4+(27 -17)×5.32 =111(元). ·······················································4 分答:小明家 10 月份的水费是 111 元.
    (2)17×3.4 =57.8(元),
    17×3.4+ (31-17)×5.32 =132.28(元),
    57.8

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