2021钦州高二下学期期末考试物理试题扫描版含答案
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这是一份2021钦州高二下学期期末考试物理试题扫描版含答案,共9页。
钦州市2021年春季学期教学质量监测参考答案高二 物 理一、单项选择题(24分)题号12345678答案CADBBDAC二、多项选择题(16分)题号9101112答案BDBCACAD13.(每空3分,共6分) (1)变小 (2)10014.(每空3分,共9分) (1)小球2的落点到管口的水平距离 (2) (3) 15.(8分)解析:(1)感应电动势最大值 ······················································2分表达式为 ················································2分(2)有效值 ························································1分由闭合电路欧姆定律得 ·····································1分电阻上所消耗的电功率 ······································2分16.(10分)解析:(1)金属杆速度最大时产生的感应电动势为 ① ···························1分 感应电流为 ② ···························1分金属杆所受的安培力大小为 ③ ····························1分根据平衡条件可得 ④ ···························1分联立①②③④并代入数据解得 ································1分 (2)设杆从静止开始运动至最大速度的过程中回路产生的总电热为,根据功能关系可得 ⑤ ··································2分根据焦耳定律可得 ⑥ ·································2分解得 ····················································1分17.(12分)解析:(1)设球质量,球下滑的过程, ·························1分代入数据可解得 ·································1分(2)设球的质量为,球进入水平轨道之后与弹簧正碰并压缩弹簧,当、相距最近时,两球速度相等,弹簧的弹性势能最大,设此时、的速度为,由动量守恒得 ············································2分由能量守恒可得弹簧的弹性势能 ······························2分联立方程,代入数据可解得 ··································1分(3) 当弹簧恢复原长时,设、的速度分别为、,之后、分离,这也就是它们的最终速度,由动量守恒可得 - 2分再根据能量守恒可得 ·······································2分联立两式,代入数据可解得, ·································1分18.(1)(5分)ABC(2)(10分)①气体做等压变化,则对于封闭气体,初状态,,, ····················································1分末状态, ················································1分由盖-吕萨克定律得,········································2分 解得 ···················································1分②气体对外界做的功 ·······················································2分根据热力学第一定律 ·······································2分解得 ····················································1分 19.(1)(5分)ACE(2)(10分)①光束通过介质的光路如图:由光路图可知,最外侧光线射出介质的折射角最大,此时入射角为,折射角为,由折射定律可得 ···························2分 ····················2分 解得 ······································································1分②设中心光线在透明固体介质中传播的速度为、时间为;离开介质到点传播的距离为、时间为,则有 ······························1分 ······························1分················1分 ······························1分则 ·····························································1分
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