2022年山东省淄博市中考数学真题（含答案）

这是一份2022年山东省淄博市中考数学真题（含答案），文件包含2022年山东省淄博市中考数学试卷docx、参考答案docx等2份试卷配套教学资源，其中试卷共15页， 欢迎下载使用。
数学试题参考答案及评分标准一、选择题：本大题共12个小题,每小题5分，共60分。题目123456789101112题号ADCDBACCDBAB二、填空题：本大题共5个小题，每小题4分，共20分。 13．a≥5    14．x（x+3）（x-3）   15．（1，3）  16．-2   17．（-2023，2022）三、解答题：本大题共7个小题，共70分。18．（本题满分8分）解：整理方程组得，                   ···················2分①×2—②得—7y=7，y=1，                       ·············································4分把y=1代入①得x—2=3，解得x=5，                  ·············································6分∴方程组的解为.       ·············································8分19．（本题满分8分）证明：∵△ABC是等腰三角形∴∠EBC＝∠DCB，·······················································2分在△EBC与△DCB中∴BE=CD，BC=CB∴△EBC≌△DCB(SAS)，··················································6分∴BD＝CE；······························································8分20．（本题满分10分）解：（1）将点A ( 1，2 )代入y =，得m=2，∴双曲线的表达式为： y＝，···········································1分把A（1，2）和B（4，0）代入y＝kx+b得：y＝，解得：，··········································3分∴直线的表达式为：y＝x+；·········································4分（2）联立 ，解得，或··························5分∵点A 的坐标为（1，2）， ∴点B的坐标为（3，）， ···············································6分∵S△AOB= S△AOB -S△AOB=OC·— OC·=×4×2—×4×=，∴△AOB的面积为；·······································8分（3）1<m<3····························································10分21．（本题满分10分）解：（1）120  99 ························································4分（2）如图：  ··············8分（3）把“礼仪”“陶艺”“园艺”“厨艺”及“编程”等五门校本课程分别记为A、B、C、D、E，画树状图如下：共有25种等可能的结果，其中小刚和小强两人恰好选到同一门课程的结果有5种，∴小刚和小强两人恰好选到同—门课程的概率P=············································10分22．（本题满分10分）解：小明能运用以上数据，得到综合楼的高度，理由如下:作EG⊥AB，垂足为G，作AH⊥CD，垂足为H，如图：····················2分由题意知，EG= BF= 40米，EF= BG= 12.88米，∠HAE= 16°= ∠AEG= 16°，∠CAH =9°，在Rt△AEG中，tan ∠AEG=，∴tan 16°=，即0.287≈，············································4分∴AG = 40×0.287=11.48（米），∴AB = AG+BG=11.48+12.88= 24.36（米），····································6分∴HD= AB =24.36米，在Rt△ACH中，AH =BD= BF＋FD=80米，tan∠CAH =，∴tan 9°= ，即0.158≈，··········································8分∴CH =80×0.158= 12.64（米），∴CD=CH＋HD = 12.64＋24.36= 37.00（米），则综合楼的高度约是37.00米.·············································10分注：结果精确到0.01米，须保留两位小数，未保留最后一步不得分！23-24．步骤待补充！步骤待补充！24．答案：解：（1）y =—x²+2x+3 （2）最大值（3）定值16