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    2009年临沂市中考数学试卷

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    2009年临沂市中考数学试卷

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    这是一份2009年临沂市中考数学试卷,共6页。试卷主要包含了选择题.,填空题,认真思考,你一定能成功!,相信自己,加油啊!等内容,欢迎下载使用。
    2009年临沂市中考数学试题一、选择题(本大题共14小题,每小题3分,共42分).1的相反数是(  A  B  C  D2.某种流感病毒的直径是0.00000008m,这个数据用科学记数法表示为(  A  B  C  D3.下列各式计算正确的是(  A  B  C D 4.下列图形中,由,能得到的是(       5.计算的结果是(  A        B    C  D6.化简的结果是(  A  B  C  D7.已知相切,的直径为9Cm的直径为4cm.则的长是(  A5cm13cm  B2.5cm  C6.5cm      D2.5cm6.5cm8.如图,OP平分,垂足分别为AB.下列结论中不一定成立的是(  A           B平分  C             D垂直平分       9.对于数据:80888585838384.下列说法中错误的有(  A.这组数据的平均数是84   B.这组数据的众数是85C.这组数据的中位数是84   D.这组数据的方差是36A1  B2  C3  D410.若,则下列式子错误的是(  A     B C      D11.如图,在等腰梯形ABCD中,,对角线于点O,垂足分别为EF,设AD=aBC=b,则四边形AEFD的周长是(  A  B  C  D12.如图是一个包装盒的三视图,则这个包装盒的体积是(  A    B   C    D13.从1234这四个数字中,任意抽取两个不同数字组成一个两位数,则这个两位数能被3整除的概率是(  A  B  C  D14.矩形ABCD中,.动点E从点C开始沿边CB向点2cm/s的速度运动,动点F从点C同时出发沿边CD向点D1cm/s的速度运动至点D停止.如图可得到矩形CFHE,设运动时间为x(单位:s),此时矩形ABCD去掉矩形CFHE后剩余部分的面积为y(单位:),则yx之间的函数关系用图象表示大致是下图中的(        二、填空题(本大题共5小题,每小题3分,共15分)15.分解因式:=_________________16.某制药厂两年前生产1吨某种药品的成本是100万元,随着生产技术的进步,现在生产1吨这种药品的成本为81万元,.则这种药品的成本的年平均下降率为______________17.若一个圆锥的底面积是侧面积的,则该圆锥侧面展开图的圆心角度数是____   _度.18.如图,在菱形ABCD中,AD的垂直平分线交对角线BD于点P,垂足为E,连接CP,则______度.19.如图,过原点的直线l与反比例函数的图象交于MN两点,根据图象猜想线段MN的长的最小值是_______      三、(本大题共3小题,共20分)20.(6分)解不等式组,并把解集在数轴上表示出来.               21.(7分)为了了解全校1800名学生对学校设置的体操、球类、跑步、踢毽子等课外体育活动项目的喜爱情况,在全校范围内随机抽取了若干名学生.对他们最喜爱的体育项目(每人只选一项)进行了问卷调查,将数据进行了统计并绘制成了如图所示的频数分布直方图和扇形统计图(均不完整).1            在这次问卷调查中,一共抽查了多少名学生?2            补全频数分布直方图;3            估计该校1800名学生中有多少人最喜爱球类活动?                      22.(7分)如图,AB是公路ll为东西走向)两旁的两个村庄,A村到公路l的距离AC=1kmB村到公路l的距离BD=2kmB村在A村的南偏东方向上.(1)求出AB两村之间的距离;2)为方便村民出行,计划在公路边新建一个公共汽车站P,要求该站到两村的距离相等,请用尺规在图中作出点P的位置(保留清晰的作图痕迹,并简要写明作法).                                         四、认真思考,你一定能成功!(本大题共2小题,共19分)23.(9分)如图,AC的直径,PAPB的切线,AB为切点,AB=6PA=5求(1的半径;(2的值.                                           24.(10分)在全市中学运动会800m比赛中,甲乙两名运动员同时起跑,刚跑出200m后,甲不慎摔倒,他又迅速地爬起来继续投入比赛,并取得了优异的成绩.图中分别表示甲、乙两名运动员所跑的路程ym)与比赛时间xs)之间的关系,根据图像解答下列问题:1)甲摔倒前,________的速度快(填甲或乙);2)甲再次投入比赛后,在距离终点多远处追上乙?                                         五、相信自己,加油啊!(本大题共2小题,共24分)25.(11分)数学课上,老师出示了问题:如图1,四边形ABCD是正方形,点E是边BC的中点.,且EF交正方形外角的平行线CF于点F,求证:AE=EF经过思考,小明展示了一种正确的解题思路:取AB的中点M,连接ME,则AM=EC,易证,所以在此基础上,同学们作了进一步的研究:1)小颖提出:如图2,如果把“点E是边BC的中点”改为“点E是边BC上(除BC外)的任意一点”,其它条件不变,那么结论“AE=EF”仍然成立,你认为小颖的观点正确吗?如果正确,写出证明过程;如果不正确,请说明理由;   2)小华提出:如图3,点EBC的延长线上(除C点外)的任意一点,其他条件不变,结论“AE=EF”仍然成立.你认为小华的观点正确吗?如果正确,写出证明过程;如果不正确,请说明理由.                                26.(13分)如图,抛物线经过三点.1)求出抛物线的解析式;2P是抛物线上一动点,过P轴,垂足为M,是否存在P点,使得以APM为顶点的三角形与相似?若存在,请求出符合条件的点P的坐标;若不存在,请说明理由;3)在直线AC上方的抛物线上有一点D,使得的面积最大,求出点D的坐标.                            2009年临沂市中考数学参考答案一、选择题(每小题3分,共42分)题号1234567891011121314答案DCCBCADDBBACAA二、填空题(每小题3分,共15分)15      1610%        17120      1872       19三、开动脑筋,你一定能做对!(共20分)20.解:解不等式,得················································2分)解不等式,得·······················································4分)所以原不等式组的解集为···············································5分)把解集在数轴上表示出来为   ·······································6分)21.解:(1(人).一共抽查了80人.·····················································2分)2(人),图形补充正确.·······················································4分)3(人).估计全校有810人最喜欢球类活动.········································7分) 22.解:(1)方法一:设的交点为,根据题意可得都是等腰直角三角形.················································1分)两村的距离为km).··················································4分)方法二:过点作直线的平行线交的延长线于易证四边形是矩形,····················································1分)中,由,可得km两村的距离为km     4分)2)作图正确,痕迹清晰.························5分)作法:①分别以点为圆心,以大于的长为半径作弧,两弧交于两点作直线②直线于点,点即为所求.·······················7分)四、认真思考,你一定能成功!(共19分)23.解:(1)连接.设的切线.·········································2分)···········································3分)中,,即的半径为·······················································5分)2)在中,························································7分)··································································9分)24.解:(1)甲.·····················································3分)2)设线段的解析式为代入,得线段的解析式为).··················································5分)设线段的解析式为分别代入     解得线段的解析式为).··················································7分)解方程组···························································9分)答:甲再次投入比赛后,在距离终点处追上了乙.·····························10分)五、相信自己,加油啊!(共24分)25.解:(1)正确.·······························1分)证明:在上取一点,使,连接·······················2分)是外角平分线,ASA).···························································5分)··································································6分)2)正确.···································7分)证明:在的延长线上取一点使,连接····································8分)四边形是正方形,ASA).···························································10分)··································································11分)26.解:(1该抛物线过点可设该抛物线的解析式为代入,解得此抛物线的解析式为··················································3分)2)存在.··························································4分)如图,设点的横坐标为点的纵坐标为时,时,解得(舍去),······················································6分)②当时,,即解得(均不合题意,舍去)时,····························································7分)类似地可求出当时,··················································8分)时,综上所述,符合条件的点·········································9分)3)如图,设点的横坐标为,则点的纵坐标为轴的平行线交由题意可求得直线的解析式为···········································10分)点的坐标为··································································11分)时,面积最大.··································································13分) 

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