47,山东省济南市平阴县2023-2024学年八年级上学期期末考试数学试题(1)
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这是一份47,山东省济南市平阴县2023-2024学年八年级上学期期末考试数学试题(1),共5页。试卷主要包含了填空题,解答题等内容,欢迎下载使用。
单项选择题(共10小题,每小题4分,满分40分)
二、填空题(共6小题,每小题4分,满分24分)
4 12. 5 13. 3
14. 60° 15. 2.5 16.
三、解答题(共10小题,满分86分,解答应写出必要的文字说明,证明过程或演算步骤)
17. 计算(本小题满分6分,每小题3分)
(1)
=·····························1分
=··································2分
=10·····································3分
(2)
=······························1分
=5+4······································2分
=9·······································3分
18.解下列方程组(本小题满分8分,每小题4分)
(1)
解:①+② 得:3x=12································1分
解 得: x=4 ③ ······························2分
将③代入②, 得 ·····························3分
所以原方程组的解是···························4分您看到的资料都源自我们平台,家威杏 MXSJ663 低至0.3/份
解:
,得···························1分
····························2分
将代入①,得 ·························3分
所以原方程组的解是·························4分
19.(本小题满分6分)
解:∵AD∥BC,∠B=80°
∴∠BAD=180°-∠B=180°-80°=100°······2分
∵AE平分∠BAD
∴··················4分
∵AD∥BC
∴∠BEA=∠DAE=50°·························6分
(本小题满分8分)
解:(1)∵在△ABC中,AB=AC, ∠A=40°,
∴·········2分
∵ AB的垂直平分线交 AC于点 E
∴ EA=EB·······················3分
∴∠ABE=∠A=40°··················4分
∴∠CBE=∠ABC-∠ABE=70°-40°=30°·········5分
5 ·······················8分
(本小题满分8分)
A组数据的中位数是 69 ,众数是 74 ;···4分
C组人数:(人)
补充如图·················6分
(人)
∴大约有1725名学生达到适宜心率·················8分
(本小题满分8分)
解:(1)设 购进A种树苗x棵,购进B种树苗y棵·················1分
由题意可得 ··························3分
解 得 ·····························4分
所以: 购进A种树苗10棵,购进B种树苗7棵
(2)①······················6分
②∵20>0
∴w随a的增大而增大
∴当a=9时,w最小,且最小值为(元)············7分
此时17-9=8
∴当购进A种树苗9棵,B种树苗8棵时,费用最省,此时费用为1200元······8分
(本小题满分8分)
如图·····················2分
写出C1的坐标 (-5,3) ;·········4分
(2)计算:△ABC的面积是 6 ···········6分
(3)点P的坐标 .··············8分
24.(本小题满分10分)
解:(1)
=··························1分
=··································2分
∵a是的小数部分
∴································4分
∴ ··················6分
=···············8分
=····················9分
=··································10分
25.(本小题满分12分)
(1)速度是 100 千米/时;···········4分
(2)路程是 100 千米;············8分
(3)解:由图象可知
甲车速度为:千米/时
乙车返回前速度为:千米/时
设:乙车返回前甲、乙两车相距40千米时,乙车行驶的时间为x小时.
则80x+120x=300-40
解得x=1.3·································10分
或80x+120x=300+40
解得x=1.7·································12分
∴乙车返回前甲、乙两车相距40千米时,乙车行驶的时间为1.3小时或1.7小时
(本小题满分12分)
(1)设 直线AP对应的函数解析式为:··················1分
代入P(1,0)、A(0,-3)
可得································2分
解得 ·································3分
所以:直线AP对应的函数解析式为····················4分
(2)设直线AP与直线x=-2交于点D,设M坐标(-2,y)
把x=-2代入直线AP,可得D(-2,-9)····················5分
∴
∴ ··················7分
解得y=3
∴M坐标(-2,3)····························8分
存在·······························9分
························12分题号
1
2
3
4
5
6
7
8
9
10
答案
A
C
B
D
C
A
D
C
B
C
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