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    江苏省徐州市区2022—2023学年上学期九年级数学期中检测试题

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    江苏省徐州市区2022—2023学年上学期九年级数学期中检测试题

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    这是一份江苏省徐州市区2022—2023学年上学期九年级数学期中检测试题,共8页。试卷主要包含了10 18,2分,, 326分,连接OD.,①证明等内容,欢迎下载使用。
    20222023学年度第一学期期中检测九年级数学参考答案   94                10.-1        11.-23      12.       13. 2    14.   15. 5        16.           1710       18  19 方程化一般形式且正确给11  ···························································3 ··························································62法一····················································10·····················································12法二,(10分)········································12法三,(10分)········································12 201··························································22)把(﹣10),(30),(03)代入抛物线·····························································4·································································73)①···························································8   -5y4·····················································10    21.(1见下图(有字母和关键格点即可), (4)   32·······················62见下图(有字母和关键格点即可),(10分)   ······················12         22.(1矩形ABCD AB=xBC=·················1由题意,得 ·························3解得 ····························································5答:此时x的值为6 m············································62设矩形养殖场的面积为·········································7由(1)得,···················································10····························································11:························································12 23(1)连接OD.  OA= ODOAD=ODA  EF垂直平分线交BDDE=BE EDB=B ·····························3C=90°OAD +B= 90º ∴∠ODA+EDB =90°·················································4ADB=180°∴∠ODE= 180°-90°=90°ODDE OD为半径DEO的切线····················································6(2) 连接OEDE=x由题意,DE=BE=xAC=6BC=8OA=2OA=OD=2,OC=4CE=8-x中,OCE=90°由勾股定理得  中,ODE=90°由勾股定理得  ····························································10x=答:DE的长为·····················································12241(方法不唯一)设抛物线的表达式为,由题意得:,把点B的坐标为-30,点C03代入得:(4)解得:(5)抛物线的解析式为·························62(方法不唯一)过点D DH⊥y由题意,DH=1,BO=3,OC=3,CH=1,OH=4,··········································8 , ········································113·····································14 251ABBC∴∠ADBCDB··················································2DB平分圆周角ADC圆中存在“爪形D”;···············································4延长DC至点E,使得CEAD,连接BE 5∵∠ADCB180°ECBDCB180°∴∠AECBCEADABBC∴△BAD≌△BCE∴∠EADB BEBD······················8∵∠ADC90°ADBCDB∴∠EADB45° ∴△BDE为等腰直角三角形····················10∴由勾股定理得,,即, CE+CD=AD+CD=··························12 2120°··································14

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