所属成套资源:2024学年江苏省各地区九年级上学期数学期中试卷(含历年真题 )
江苏省徐州市区2022—2023学年上学期九年级数学期中检测试题
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这是一份江苏省徐州市区2022—2023学年上学期九年级数学期中检测试题,共8页。试卷主要包含了10 18,2分,, 326分,连接OD.,①证明等内容,欢迎下载使用。
2022—2023学年度第一学期期中检测九年级数学参考答案 9.4 10.-1 11.(-2,3) 12. 13. 2 14. 15. 5 16. 17.10 18. 19. 方程化一般形式且正确给1分(1) ···························································3分 ··························································6分(2)法一:,····················································10分∴,.·····················································12分法二:,(10分)∴,.········································12分法三:,(10分)∴,.········································12分 20.(1)··························································2分(2)把(﹣1,0),(3,0),(0,3)代入抛物线中得中·····························································4分·································································7分(3)①···························································8分 ②-5≤y≤4·····················································10分 21.(1)见下图(有字母和关键格点即可), (4分) 32·······················6分(2)见下图(有字母和关键格点即可),(10分) ······················12分 22.(1)矩形ABCD, AB=xBC=·················1分由题意,得 .·························3分解得 ,. 当. 当····························································5分答:此时x的值为6 m.············································6分(2)设矩形养殖场的面积为·········································7分由(1)得,···················································10分····························································11分答:当························································12分 23.(1)连接OD. ∵OA= OD,∴∠OAD=∠ODA ∵EF垂直平分线交BD,∴DE=BE ∴∠EDB=∠B ·····························3分∵∠C=90°,∴∠OAD +∠B= 90º ∴∠ODA+∠EDB =90°·················································4分∵∠ADB=180°∴∠ODE= 180°-90°=90°∴OD⊥DE ∵OD为半径∴DE是⊙O的切线····················································6分(2) 连接OE,设DE=x由题意,DE=BE=x,∵AC=6,BC=8,OA=2∴OA=OD=2,OC=4,CE=8-x∵在中,∠OCE=90°,由勾股定理得 ∴, ∵在中,∠ODE=90°,由勾股定理得 ∴, ····························································10分∴,x=,答:DE的长为·····················································12分24.(1)(方法不唯一)设抛物线的表达式为,由题意得:,把点B的坐标为(-3,0),点C(0,﹣3)代入得:,(4分)解得:,(5分)∴抛物线的解析式为;·························6分(2)(方法不唯一)过点D作 DH⊥y轴由题意,DH=1,BO=3,OC=3,CH=1,OH=4,··········································8分 , ∴········································11分(3)·····································14分 25.(1)①证明:∵AB=BC,∴∠ADB=∠CDB,··················································2分∴DB平分圆周角∠ADC,∴圆中存在“爪形D”;···············································4分②延长DC至点E,使得CE=AD,连接BE, 5分∵∠A+∠DCB=180°∠ECB+∠DCB=180°∴∠A=∠ECB∵CE=AD,AB=BC∴△BAD≌△BCE∴∠E=∠ADB, BE=BD······················8分∵∠ADC=90°,∠ADB=∠CDB∴∠E=∠ADB=45° ∴△BDE为等腰直角三角形····················10分∴由勾股定理得,,即, ∴CE+CD=AD+CD=··························12分 (2)120°··································14分
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