2023山东省某重点校高二上学期期末考试物理PDF版含答案(可编辑)
展开2022-2023学年度第一学期期末学业水平检测
高二物理答案及评分标准
一、单项选择题:本大题共8小题,每小题3分,共24分。
1.A 2.D 3.B 4.A 5.B 6. D 7.C 8.C
二、多项选择题:本大题共4小题,每小题4分,共16分,选不全得2分,有选错得0分。
9.AC 10.AB 11.ACD 12.BC
三、非选择题
13.(6分)
(1)C(1分);摆角过大,已不能将小球的运动看作简谐运动。(1分)
(2)偏小(2分)
(3)或(2分)
14.(9分)
(1) ×1(2分);30(2分)
(2) 丙(2分);C(1分)
(3)偏小(1分);电压表的分流(1分)
15.(8分)
(1)由图像可知:T=6s,波长λ=12m·······························(2分)
则波的传播速度:v=m/s·····································(2分)
(2)质点位置与时间的关系式为:y=Asint···························(1分)
当t=9.5s,y=-1,因此坐标为(3m,-1cm)····················(1分)
(3)当t=9.5内质点走过的路程s=6A+1=13cm························(2分)
评分标准:第1问,4分;第2问,2分;第3问,2分。共8 分。
16.(10分)
(1)在平衡位置:有F-kx0=0,x0=·······························(2分)
规定向左为正,当BC向左偏离平衡位置为x时
回复力(即合外力)为F回=F-k(x+x0)
综上解得F回=-kx,因此得证。·······························(2分)
(2)撤去F后,B、C回到弹簧原长处:
由简谐振动的知识可知:弹簧压缩到最短时,BC前进的位移s=2x0·····(1分)
Fs=················································(1分)
解得:v1=···············································(1分)
到弹簧最长时AB共速:mv1=3mv2······························(1分)
根据能量守恒: EP=-······································(1分)
解得:EP=···············································(1分)
评分标准:第1问,4 分;第2问,6 分。共10 分。
17.(12分) 光路图如图所示
(1)由几何知识可知△AOE与△BEF相似
且OE+EF=14cm··············(1分)
解得OE=6cm············(1分)
设玻璃砖厚为d
△AOE与△DMH相似
,解得:d=4cm··········(2分)
(2)入射角的正弦:································(1分)
折射角的正弦:·······························(1分)
折射率:·····································(2分)
(3)光在玻璃砖内地传播速度m/s······················(1分)
经过的路程: ································(1分)
所用的时间:·································(2分)
评分标准:第1问,4分;第2问,4分;第3问,4分。共 12分。
18.(15分)全科试题免费下载公众号《高中僧课堂》
(1)扇形电场的电势差为:···························(1分)
粒子在加速电场中根据动能定理有:················(1分)
解得速率:···································(1分)
粒子在磁场中的运动轨迹如右图所示,可得粒子在磁场中做匀速圆周运动的半径:
············································(1分)
由:········································(1分)
解得:······································(1分)
(2)打到荧光屏上的竖直高度为:·····················(2分)
(3)当竖直穿出磁场时,粒子在磁场中运动的半径为R
由于:
可知加速电压: U′=··························(2分)
可得:-= . ·································(1分)
解得:x= ···································(1分)
(4)扫过的区域形状右图所示
············································(3分)
评分标准:第1问,6分;第2问,2分;第3问,4分;第4问,3 分。共15 分。
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