





2022年山东省淄博市中考数学真题(含答案)
展开数学试题参考答案及评分标准
一、选择题:本大题共12个小题,每小题5分,共60分。
题目 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
题号 | A | D | C | D | B | A | C | C | D | B | A | B |
二、填空题:本大题共5个小题,每小题4分,共20分。
13.a≥5 14.x(x+3)(x-3) 15.(1,3) 16.-2 17.(-2023,2022)
三、解答题:本大题共7个小题,共70分。
18.(本题满分8分)
解:整理方程组得, ···················2分
①×2—②得—7y=7,
y=1, ·············································4分
把y=1代入①得x—2=3,
解得x=5, ·············································6分
∴方程组的解为. ·············································8分
19.(本题满分8分)
证明:∵△ABC是等腰三角形
∴∠EBC=∠DCB,·······················································2分
在△EBC与△DCB中
∴BE=CD,BC=CB
∴△EBC≌△DCB(SAS),··················································6分
∴BD=CE;······························································8分
20.(本题满分10分)
解:(1)将点A ( 1,2 )代入y =,得m=2,
∴双曲线的表达式为: y=,···········································1分
把A(1,2)和B(4,0)代入y=kx+b得:
y=,解得:,··········································3分
∴直线的表达式为:y=x+;·········································4分
(2)联立 ,解得,或··························5分
∵点A 的坐标为(1,2),
∴点B的坐标为(3,), ···············································6分
∵S△AOB= S△AOB -S△AOB=OC·— OC·
=×4×2—×4×
=,
∴△AOB的面积为;
·······································8分
(3)1<m<3····························································10分
21.(本题满分10分)
解:(1)120 99 ························································4分
(2)如图:
··············8分
(3)把“礼仪”“陶艺”“园艺”“厨艺”及“编程”等五门校本课程分别记为A、B、C、D、E,画树状图如下:
共有25种等可能的结果,其中小刚和小强两人恰好选到同一门课程的结果有5种,
∴小刚和小强两人恰好选到同—门课程的概率P=
············································10分
22.(本题满分10分)
解:小明能运用以上数据,得到综合楼的高度,理由如下:
作EG⊥AB,垂足为G,作AH⊥CD,垂足为H,如图:
····················2分
由题意知,EG= BF= 40米,EF= BG= 12.88米,∠HAE= 16°= ∠AEG= 16°,∠CAH =9°,
在Rt△AEG中,
tan ∠AEG=,
∴tan 16°=,即0.287≈,············································4分
∴AG = 40×0.287=11.48(米),
∴AB = AG+BG=11.48+12.88= 24.36(米),····································6分
∴HD= AB =24.36米,
在Rt△ACH中,AH =BD= BF+FD=80米,
tan∠CAH =,
∴tan 9°= ,即0.158≈,··········································8分
∴CH =80×0.158= 12.64(米),
∴CD=CH+HD = 12.64+24.36= 37.00(米),
则综合楼的高度约是37.00米.·············································10分
注:结果精确到0.01米,须保留两位小数,未保留最后一步不得分!
23-24.步骤待补充!
步骤待补充!
24.答案:解:(1)y =—x²+2x+3
(2)最大值
(3)定值16
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